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Overview: The article discusses the vital role of feedback amplifiers in electronic circuits and examines their types. It also highlights the desirable effects of negative feedback on signal amplification, enhancing overall performance. To improve the reliability and performance of amplification circuits, feedback amplifiers play an essential role in electronics. A feedback loop allows these amplifiers to fine-tune and enhance their output, leading to more accurate and dependable operation. What is feedback?The term "feedback" describes the process of redirecting a portion of an amplifier's output signal into an input signal. Here, the input to the circuit is a portion of the output signal that has been added or reduced to the source signal. Consequently, the amount of feedback may rise or fall based on the operation of adding or subtracting the signal from the source signal. What is a feedback amplifier?An important part of the amplifier is the feedback circuit, which works by feeding back some of the signal's output to the input. These amplifiers have several uses since they provide better control over many parameters.Types of FeedbackPositive FeedbackPositive feedback occurs when feedback is used to increase the input signal. Positive feedback adds to the input signal, and the new input to the circuit is greater than the source signal. For this reason, it is also known as regenerative feedback. Positive feedback occurs when the feedback energy (voltage or current) is in phase with the input signal. Fig. 1 shows that both the amplifier and the feedback network create a 180° phase shift. As a result, the sum of the 360° phase shift around the loop occurs, and the feedback voltage (Vf) becomes in phase with the input signal (Vin). Fig. 1 Illustration of the positive feedback amplifier. Source: Rakesh Kumar, Ph.D.The positive feedback increases the amplifier's gain. However, it has the drawbacks of increased distortion and instability. Positive feedback is, therefore, rarely used in amplifiers. Positive feedback is utilized in oscillators, multivibrator circuits, and some active filters. Negative FeedbackNegative feedback is defined as feedback that decreases the input signal. Degenerative feedback, also known as negative feedback, occurs when the signal feedback is out of phase with the input signal by 180°. Negative feedback occurs when the input signal's voltage or current is out of phase with the feedback energy. The feedback network is supposed to introduce no phase shift, or 0° phase shift, however, the amplifier introduces a 180° phase change into the circuit, as seen in Fig. 2. As a result, the input signal (Vin) and the feedback voltage (Vf) are 180° out of phase. Fig. 2 Illustration of the negative feedback amplifier. Source: Rakesh Kumar, Ph.D. Advantages of Negative Feedback AmplifierA negative feedback amplifier provides several benefits, including lower distortion, more stable gain, wider bandwidth, and better input and output impedances. Negative feedback is used in amplifiers and other control circuits to improve stability. Gain StabilityGain is defined as the ability of a circuit to increase the power or amplitude of a signal. Gain is the ratio of output to input signal in an amplifier and can be expressed as A, as shown in the equation. It can be a voltage gain, a current gain, or a power gain. Gain is typically a unitless measurement.A = Vout / Vin Negative voltage feedback improves the stability of amplifier gain by making it independent of transistor characteristics and supply voltage fluctuations. Desensitizing the gain refers to making the overall gain of an amplifier less sensitive to variations in the amplifier's internal components or operating conditions. The gain only depends on the feedback circuit's parameters. Feedback circuits, which are typically resistive networks, are not impacted by temperature, transistor settings, or frequency changes. Consequently, the gain of the amplifier is extremely stable. This is one of the key benefits of using negative feedback in amplifiers. Non-Linear DistortionNegative feedback plays a crucial role in reducing non-linear distortion and makes the gain of the amplifier almost constant. It helps maintain a more proportional relationship between input and output signals, reducing non-linear distortions that occur when the amplifier operates outside its linear region. Improved BandwidthNegative feedback improves the frequency response and extends the bandwidth of the amplifier. This ensures that the amplifier can handle a wider range of frequencies more effectively, maintaining consistent gain across the spectrum. Input and Output ImpedanceNegative feedback in amplifiers significantly influences both input and output impedances, enhancing the overall performance and stability of the amplifier. NoiseDepending on whether a transistor or tube is employed, an amplifier might have a variety of noise sources. Negative feedback helps reduce the noise in the output signal. To conclude, negative feedback lowers the amplifier's gain. At the same time, negative feedback reduces distortion and noise. This trade-off is generally beneficial, as the improved linearity and reduced distortion often outweigh the loss in gain. A feedback amplifier to considerLM6172The LM6172 is a high-speed, low-power, low-distortion, dual-voltage feedback amplifier designed by Texas Instruments. It is particularly noted for its excellent DC and AC performance, making it suitable for a wide range of applications. The LM6172 boasts a very high slew rate of 3000 V/μs, which allows it to handle rapid changes in input signals without significant delay. It has a unity-gain bandwidth of 100 MHz, ensuring stable operation even at high frequencies.The amplifier is designed to operate efficiently, consuming minimal power, which is crucial for battery-operated and portable devices. The LM6172 features low total harmonic distortion and can operate over a wide supply voltage range from ±2.5V to ±18V, providing flexibility for various design requirements. It operates over a broad temperature range from -55°C to 125°C, making it suitable for industrial and military applications. The LM6172 is available in various packages, including 8-DIP and surface-mount options, providing flexibility for different design and manufacturing requirements. Summarizing the Key PointsFeedback amplifiers play a crucial role in enhancing the efficiency and stability of amplification circuits in electronics.Understanding the types of feedback, such as positive and negative, is essential for optimizing signal amplification.Negative feedback offers benefits like reduced distortion, improved stability, wider bandwidth, and enhanced input/output impedances.The LM6172 amplifier by Texas Instruments exemplifies a high-speed, low-power, low-distortion feedback amplifier suitable for various applications. ReferenceAyobamidele, Segun & Oyebola, Blessed. (2018). Feedback Amplifier, Its Operation, Effect Importance and Connecting Types: A Review. 16-32.ALL ABOUT ELECTRONICS, “Introduction to Feedback Amplifier | The concept of Negative Feedback and its advantages,” July 7, 2024, https://www.youtube.com/watch?v=__8f6AXenYo.
Rakesh Kumar, Ph.D. On 2024-07-27
Introduction to Amplifier GainSummary (2026 Update): From 5G RF front-ends to precision IoT sensors—Gain remains the fundamental metric of signal amplification. It quantifies the ratio of output to input for voltage, current, or power, typically expressed in decibels (dB). This guide covers the essential physics, calculation methods, and frequency response analysis required for high-performance circuit design in 2026.In electrical circuits, Gain generally refers to the degree of increase in current, voltage, or power of components, circuits, equipment, or systems. It is specified in decibels (dB), meaning the unit of gain is generally dB, which represents a relative value rather than an absolute unit like Volts or Amps. In short, its general meaning is the magnification factor. In electronics, it is strictly the ratio of the signal output to the signal input of a system. For example, antenna gain is a parameter that represents the radiation concentration of a directional antenna. But what exactly is amplifier gain in the context of modern semiconductors? How do you calculate it using 2026 industry standards? Read the following technical notes for a deep dive.Ⅰ Amplifier Gain Fundamentals1.1 Definition and ContextAmplifier gain is the logarithm of the ratio of output power to input power, used to express the magnitude of power amplification. It also refers to the magnification of voltage or current. The decibel (dB) is the standard unit. The total magnification of an electronic system is often several thousand (e.g., Low Noise Amplifiers) to millions (e.g., Operational Amplifiers). For example, a modern digital radio receiver might need to amplify a signal 20,000 times or more from the antenna to the DSP or speaker. Using linear numbers makes calculations unwieldy. In decibels, we take a logarithm, making the numbers manageable. Crucially, when amplifiers are cascaded (connected in series), the total linear magnification is multiplied, but the total gain in dB is additive, simplifying system design.1.2 Gain Representation in Decibels (dB)Voltage gain Av(dB) = 20log(|Av|)The voltage gain in decibels is 20 times the base-10 logarithm of the voltage ratio (Output Voltage / Input Voltage).Current gain Ai(dB) = 20log(|Ai|)The current gain in decibels is 20 times the base-10 logarithm of the current ratio.Power gain Ap(dB) = 10log(Ap). Note the factor is 10, not 20. Power gain = Output Power / Input Power.Why use decibels? Beyond simple convenience, human perception (like hearing) is logarithmic. A gain of 100,000,000 times (linear) is awkward to document. Converted to dB, it becomes 160dB, which is standard engineering notation. This principle mirrors why computing uses binary or hexadecimal. Engineers can easily convert between linear magnification and decibels depending on the simulation or datasheet requirement.Ⅱ Types of Amplifier Gain2.1 Voltage Gain (Av)Av = Vo / Vi means that voltage gain equals the amplifier's output voltage divided by the input voltage. This is the primary metric for Voltage Amplifiers.🔺 Open Loop Voltage Gain (AVOL)In the absence of negative feedback, the amplification factor of an operational amplifier (Op-Amp) is called Open-Loop Gain. Ideally, this is infinite. In practice, modern precision Op-Amps (like the OPA series replacing legacy chips) feature gains between $10^5$ to $10^7$. Representations include dB (e.g., 106dB) or V/mV. While legacy chips like the μA741C or LM318 had typical values around 200V/mV, 2026-era rail-to-rail amplifiers offer significantly higher linearity. We use the "virtual ground" assumption in calculations because the immense AVOL forces the differential input voltage to near zero.The Ideal Op Amp Characteristics:1) Open loop gain is infinite.2) Input impedance is infinite (no loading effect), and output impedance is 0.3) Bandwidth is infinite (instantaneous response).Video: How To Calculate the Voltage Gain of a Transistor Amplifier🔺 Closed Loop Voltage GainThis refers to the gain of the entire circuit after a negative feedback loop is applied. Feedback stabilizes the gain and widens bandwidth. The formula is: voltage gain = 20log(Vo / Vi).🔺 IF (Intermediate Frequency) Voltage GainThe IF voltage gain (Avm) refers to the maximum voltage gain within the passband—specifically the frequency range where the voltage amplitude remains above 0.707 of the maximum (the -3dB points).2.2 Current Gain (Ai)Ai = Io / Ii defines current gain as the output current divided by the input current. These circuits are known as Current Amplifiers (or Current Mirrors in IC design).2.3 Transimpedance Gain (Rm)Ar = Vo / Ii. Here, the gain represents Output Voltage / Input Current. This topology is called a Transimpedance Amplifier (TIA), critical in 2026 for photodiode sensors and fiber optic receivers.2.4 Transconductance Gain (gm)A = Io / Vi. Transconductance gain is the ratio of Output Current to Input Voltage. These are Transconductance Amplifiers (OTAs), often used as the input stage in modern Op-Amps. Ⅲ Fully Differential Amplifier GainA fully differential amplifier (FDA) is standard in modern high-speed ADC drivers. It features four distinct gain metrics based on Common Mode (CM) and Differential Mode (DM) signals.Adm (Differential Gain): The gain from differential input to differential output. This is the desired signal amplification.Acm (Common Mode Gain): The gain from common-mode input to common-mode output. Ideally, this should be zero to reject noise.Adcm (Mode Conversion - Diff to CM): Gain from differential input to common-mode output.Acdm (Mode Conversion - CM to Diff): Gain from common-mode input to differential output.Design Goal: Maximize Adm while minimizing Acm, Adcm, and Acdm. A high Adm ensures strong signal integrity. A low Acm is crucial; if Acm is non-zero in cascaded stages, common-mode noise (like 60Hz hum or EMI) amplifies, causing "rail saturation." Adcm and Acdm must be minimized to prevent signal distortion and feedback loops that can destabilize the amplifier. In 2026 designs, Common-Mode Rejection Ratio (CMRR) is the key spec that aggregates these parameters. Ⅳ Frequency Response and Gain CalculationCapacitors in an amplifier circuit dictate the frequency response. We analyze gain across three bands: Low Frequency (LF), Intermediate Frequency (IF), and High Frequency (HF).Figure: The Relationship between Gain and Frequency (Bode Plot)1) Intermediate Frequency (IF):Coupling/Bypass Capacitors → Short Circuit.Transistor Parasitic Capacitance → Open Circuit.The gain expression is frequency-independent (flat). This is the nominal gain of the amplifier.2) Low Frequency (LF):Coupling and bypass capacitors are significant here. Their impedance rises as frequency drops, reducing gain. The circuit acts as a High-Pass Filter.3) High Frequency (HF):Internal transistor capacitances (Cpi, Cmu) and stray load capacitances dominate. As frequency rises, these act as short circuits, shunting the signal to ground. The circuit acts as a Low-Pass Filter.Gain Function and Corner Frequencies (S-Domain Analysis)In the complex frequency domain (s-domain), Capacitance = 1/sC and Inductance = sL. The system function A(s) is a ratio of polynomials:Factoring the numerator and denominator reveals the zeros and poles:Key Characteristics:1) For physical stability, the number of zeros (m) must be ≤ poles (n).2) In low-frequency amps, poles are real numbers corresponding to RC time constants.The gain function is split into three bands:Determining the Lower Corner Frequency (fL):At low frequencies, s → ∞ relative to the low poles. The response is governed by coupling capacitors. If one pole is significantly larger (closer to the passband) than the others, it is the Dominant Pole (p1).Approximation using the Dominant Pole concept:......(a)Determining the Upper Corner Frequency (fH):At high frequencies, transistor internal capacitances dominate. Here, we look for the smallest pole (closest to the passband) which acts as the dominant high-frequency pole.The simplified derivation for bandwidth (fBW) typically relies on identifying these dominant poles in the transfer function. Ⅴ FAQ: Common Questions on Amplifier Gain1. How is gain strictly defined in electronics?Gain is the dimensionless ratio of Output / Input. While it has no physical units (Volts/Volts cancel out), it is almost always expressed in Decibels (dB) to handle large magnitudes comfortably. The symbol is "A" (e.g., Av for Voltage Gain).2. What is the difference between Voltage, Current, and Power Gain?Voltage Gain (Av) is Vout/Vin. Current Gain (Ai) is Iout/Iin. Power Gain (Ap) is Pout/Pin. Note that Power Gain is the product of Voltage and Current Gain. In dB: Power Gain uses 10log, while Voltage/Current uses 20log.3. What is the typical current gain (Alpha) of a Common-Base amplifier?In a Common-Base (CB) configuration, the current gain is called Alpha (α). Since the emitter current is the sum of base and collector current (IE = IB + IC), and the output is taken from the collector, the output is always slightly less than the input. Thus, α is always < 1 (typically 0.95 to 0.99).4. How do you calculate the gain of a Differential Amplifier?For a standard differential amp with balanced resistors (R1=R2=R3=R4), it is a Unity Gain device where Vout = V2 - V1. If resistors differ, the gain is determined by the ratio of the feedback resistor to the input resistor.5. What defines an "Ideal" Op-Amp in 2026 theory?An ideal op-amp is a theoretical construct with: Infinite Open Loop Gain, Infinite Input Impedance (draws no current), Zero Output Impedance (drives any load), and Infinite Bandwidth. Real-world components strive to approach these limits using advanced CMOS or BiCMOS processes.6. Why is Op-Amp gain so high?Op-Amps are designed as multi-stage differential amplifiers. They utilize active loads (current mirrors) rather than passive resistors internally, allowing them to achieve massive Open Loop Gains (often >100,000x) to ensure precise performance when closed-loop feedback is applied.7. How do I find the gain of an Inverting Op-Amp?The formula is straightforward: Gain (Av) = - (Rf / Rin). Rf is the feedback resistor, and Rin is the input resistor. The negative sign indicates a 180-degree phase shift.{ "@context": "https://schema.org", "@type": "TechArticle", "headline": "Comprehensive Guide to Amplifier Gain: Formulas, Types, and Calculation (2026 Edition)", "description": "A deep dive into Amplifier Gain in electronics. Learn about Voltage, Current, and Power gain, decibel conversion, frequency response analysis, and modern fully differential amplifier theories.", "datePublished": "2019-01-01", "dateModified": "2026-01-05", "author": { "@type": "Organization", "name": "Kynix Semiconductor" }, "mainEntity": { "@type": "FAQPage", "mainEntity": [ { "@type": "Question", "name": "How is gain strictly defined in electronics?", "acceptedAnswer": { "@type": "Answer", "text": "Gain is the dimensionless ratio of Output divided by Input. While it has no physical units, it is almost always expressed in Decibels (dB). The symbol is usually A." } }, { "@type": "Question", "name": "What is the formula for Voltage Gain in dB?", "acceptedAnswer": { "@type": "Answer", "text": "Voltage Gain in dB is calculated as 20 * log10(Vout / Vin)." } }, { "@type": "Question", "name": "What is the difference between Voltage, Current, and Power Gain?", "acceptedAnswer": { "@type": "Answer", "text": "Voltage Gain (Av) is Vout/Vin. Current Gain (Ai) is Iout/Iin. Power Gain (Ap) is Pout/Pin. In dB conversion, Voltage and Current use 20log, while Power uses 10log." } }, { "@type": "Question", "name": "What is the current gain (Alpha) of a Common-Base amplifier?", "acceptedAnswer": { "@type": "Answer", "text": "In a Common-Base configuration, the current gain (Alpha) is always less than 1 (unity), typically between 0.95 and 0.99." } }, { "@type": "Question", "name": "How do you calculate the gain of an Inverting Op-Amp?", "acceptedAnswer": { "@type": "Answer", "text": "The gain is calculated using the formula: Gain = - (Rf / Rin), where Rf is the feedback resistor and Rin is the input resistor." } } ] }}
Ivy On 2022-02-22
Introduction RF power amplifier is an important part of various wireless transmitters. In the front-end circuit of the transmitter, the power of the RF signal generated by the modulation oscillator circuit is very small, and it needs to go through a series of amplification-buffer stage, intermediate amplification stage, and final power amplification stage to obtain enough RF power before feeding. In order to obtain a sufficiently large RF output power, a RF power amplifier must be used. RF Power Amplifier Design: The Basics Catalog Introduction Ⅰ Requirements of RF Power Amplifier Ⅱ Types of Power Amplifier in Use Ⅲ Parameters of RF Power Amplifier Design Ⅳ Key Feature: Non-Linearity 4.1 Nonlinear Characteristics 4.2 Influence of Nonlinear Characteristics Ⅴ FAQ Ⅰ Requirements of RF Power Amplifier With the vigorous development of modern digital mobile communication technology, users have more requirements on the performance of wireless communication equipment. To achieve stable and high-speed data transmission in various environments is one of the main goals of future mobile communication system researchers. The RF power amplifier is the last stage of the transmitter. It amplifies the modulated frequency band signal to the required power, ensuring that the receiver in the coverage area can receive a satisfactory signal level, but it cannot interfere too much with the communication of adjacent channels, and meanwhile try to keep the amplified high-power signal without distortion. The requirements of these different aspects make the users of power amplifiers have to consider many factors in all aspects. So you should get a full knowledge of RF power amplifiers. Figure 1. Classic RF Power Amplifier Circuit Ⅱ Types of Power Amplifier in Use What are the main types of RF amplifiers for such an important device?1) According to the operating frequency bandsAccording to the working frequency band, it can be divided into narrowband RF power amplifier and broadband RF power amplifier. The former generally uses frequency selective networks as load circuits, such as LC resonant circuits. The latter does not use the frequency selection network as the load loop, but employs the transmission line with a wide frequency response as the load.2) According to the network propertiesAccording to the nature of the matching network, power amplifiers can be divided into non-resonant power amplifiers and resonant power amplifiers. The matching network of the non-resonant power amplifier is a non-resonant system, such as high-frequency transformers, transmission line transformers and other non-resonant systems, and its load properties are purely resistive, where this is also called reactance properties.3) According to current conduction angleBased on it, RF power amplifiers can be divided into class A, AB, B, C, D, E and so on. The differences between these categories can be seen in the following table: Classification Conduction Angle Efficiency Linearity Application Class A Θ=360° ≤30% Very good Small Signal Low Power Amplification Class B Θ=180° ≤60% Lower than class A For High Power Class C Θ<180° About 60% Nonlinear amplifier For High Power Class AB 180°<Θ<360° 30%~60% Better than class B Small signal works in class A, large signal works in class B Class D Work in switch mode 80% Very good, only good for low frequencies Switch mode amplifier Class E Work in switch mode 90% Completely nonlinear amp Switch mode amplifier In the classification of amplifiers, we often talk about amplifiers of class A to E according to the conduction angle. Class A power amplifier is a linear amplifier, its response to the sine-wave input is a sine-wave output, generally without distortion amplification, and the output frequency is the same as the input frequency. Since class A amplifiers do not require additional filtering circuitry, their packages can be small and cost less. The output of a class B amplifier is a half sine wave of the input, resulting in half-wave distortion, which produces many harmonics. The output power and efficiency of the class C working state are the highest among these working states, and most of the amplifiers used for radio frequency work in the class C. Figure 2. Class A Amplifier Load Curve Ⅲ Parameters of RF Power Amplifier Design RF power amplifiers are electronic circuits that comprehensively consider issues such as output power, excitation level, power consumption, distortion, efficiency, size and weight. In the transmitting system, the output power of the RF power amplifier can be as small as mW and as large as several kW, but this refers to the output power of the final power amplifier. In order to achieve high power output, the last stage must have a sufficiently high excitation power level. At the same time, it has other important indicators, as follows:1) Operating FrequencyGenerally speaking, it refers to the linear operating frequency range of the amplifier. If the frequency starts at DC, the amplifier is considered to be a DC amplifier.2) GainThe working gain is the main indicator to measure the amplification ability of the amplifier. Here it is defined as the ratio of the power delivered to the load by the amplifier output port to the power actually delivered by the signal source to the amplifier input port.Gain flatness refers to the variation range of amplifier gain in the entire operating frequency band under a certain temperature, and is also a main indicator of the amplifier. Figure 3. Output Power and 1dB Compression Point (P1dB) Referring to the Figure 3, when the input power exceeds a certain amount, the gain of the transistor begins to decrease, and the end result is that the output power saturates. When the gain of the amplifier deviates from a constant or is 1dB lower than other small signal gains, this point is the famous 1dB compression point (P1dB). Generally speaking, the power capacity of an amplifier is expressed by the 1dB compression point.3) EfficientSince the power amplifier is a power component, it needs to consume the supply current. Therefore, the efficiency of the power amplifier is extremely important to the efficiency of the whole system. Power efficiency is the ratio of the RF output power of the amplifier to the DC power supplied to the transistors.ηp=RF Output Power/DC Input Power4) Intermodulation Distortion (IMD)Intermodulation distortion refers to the mixed components of two or more input signals with different frequencies passing through a power amplifier. This is due to the nonlinear nature of the amplifier. Among them, because the third-order intermodulation product is very close to the fundamental signal, it has the greatest influence, so the third-order intermodulation is the most important consideration for the related products. The lower the third-order intermodulation product, the better.5) Third-order Intermodulation Cut-off Point (IP3)The intersection point of the extension line of the fundamental wave signal output power and the extension line of the third-order intermodulation in Fig is called the third-order intermodulation cut-off point, which is represented by the symbol IP3. It is also an important indicator of nonlinearity. When the output power is constant, the greater the output power of the third-order intermodulation cut-off point, the better the linearity of the power amplifier.6) Dynamic RangeThe dynamic range of a power amplifier generally refers to the difference between the minimum detectable signal and the maximum input power in the linear operating region. Naturally, this value must be as large as possible.7) Harmonic DistortionWhen the input signal increases to a certain level, the power amplifier will generate a series of harmonics due to its work in the nonlinear region. For high-power amplifier systems, filters are generally required to reduce harmonics below 60dBc.8) Input/Output VSWR (Voltage Standing Wave Ratio)This is also a very important indicator of how well the amplifier matches the overall system. The deterioration of the input-output ratio will lead to the deterioration of the gain fluctuation and group delay of the system. However, it is difficult to design a power amplifier with a high VSWR. In general systems, the input VSWR of the power amplifier is required to be lower than 2:1.The main technical indicators of RF power amplifiers are output power and efficiency. Therefore how to improve them is the core of the design goals of RF power amplifiers. Usually in the RF power amplifier, the fundamental frequency or a certain harmonic can be selected by the LC resonant circuit to achieve distortion-free amplification. In addition to this, the harmonic components in the output should be as small as possible to avoid interference with other channels. Figure 4. Increase the Power of the RF Input Signal Ⅳ Key Feature: Non-Linearity In an ideal amplifier, the output signal should faithfully reflect the input signal, that is, the waveform should be the same. But in fact, for many reasons, the input signal cannot be exactly the same waveform as the input signal, which is called amplifier distortion.Amplifier distortion mainly includes frequency distortion (linear distortion) and waveform distortion (non-linear distortion). The former mainly refers to the difference in gain and delay of the amplifier for different frequency components; the latter refers to the same frequency, the output signal and the input signal are not linear. Frequency distortion is represented by spectral changes in the frequency domain, while nonlinear distortion is represented by changes in the time-domain waveform. Non-linear distortion is different from frequency distortion mainly because a large number of new frequency components are generated. The nonlinear distortion of the power amplifier is mainly discussed here. 4.1 Nonlinear Characteristics From the small-signal model and input characteristic curve of an ideal transistor, it can be seen that the transistor amplifier itself is not an ideal linear device, and at the same time, due to the influence of parasitic parameters, the linearity is further reduced. But within a certain power range, the transistor can be regarded as linear amplification. For power amplifier designers, how to obtain higher output power and improve linearity is the key.For a transistor amplifier, its volt-ampere characteristics can be described as follows: A power series expansion can be used to describe the volt-ampere characteristics of the device: In the formula, an(n=0,1,2,3,…) is a coefficient related to the circuit characteristics. Usually, the larger the n, the smaller the value of the coefficient an. When the nonlinear device in the circuit is represented by a power series, the number of series terms taken depends entirely on the magnitude of the signal amplitude and the required precision. 4.2 Influence of Nonlinear Characteristics The influence of the nonlinear characteristics of the device on the amplifier can be discussed in two cases. One is when there is only one signal at the input end, and the other is when the input end has one to two other signals in addition to the useful signal.🔺Only one signal at the inputLet the signal at the input end be , and substitute it into formula 2, at this time there is When the amplitude of the input signal is large and the effect of the cubic term must be considered, the fundamental frequency signal obtained from formula 2 is: Figure 5. 1dB Compression Point (PA) A3 in formula 3 is usually a negative value, that is, y1(t) decreases as the input signal amplitude increases, a phenomenon called gain compression.The "1dB compression point" is often used in engineering to measure the linear performance of the device. The 1dB compression point is defined as the input signal power P1dB that reduces the gain by 1dB from the linear gain. As shown in Figure 5. According to the definition of 1dB compression point and formula 3, we can get 🔺Two signals at the input.The signal amplified at the input end of the amplifier is generally not a single tone signal, but a spectral signal composed of a certain bandwidth. Due to the nonlinearity of the device, a large number of combined interference frequency components other than the useful signal will be generated at the output end. In addition, the combined frequency components of two or more interfering signals may also cause interference to the useful signal. Have an assumption: Substitute into formula 1, where It can be seen from the above formula that the fundamental frequency components of ω1 and ω2 are generated by the first and third power terms: A total of multiple frequency components are generated: ω1 , ω2 , ω1 ± ω2, 2ω1 - ω2, 2ω2 - ω1 , 3ω1 - 2ω2, 3ω2 - 2ω1.The difference frequency 2ω1 - ω2, 2ω2 - ω1 in the combined frequency is generated by the cubic term. The combination of these two signal frequencies is just within the sideband range of the signal frequency, which may cause interference to adjacent channels, and is one of the main indicators of transmission signal. Figure 6. Intermodulation Signal Interference This interference is caused by the mutual modulation of the two signals, so it is called intermodulation interference. At the same time, it is generated by a cubic term, so it is also called third-order intermodulation interference in engineering.When the third-order intermodulation interference is an important indicator of the communication machine, it is often measured by the intermodulation distortion ratio IMR and the third-order intermodulation blocking point IP3 in engineering. IMR is defined as the ratio of the amplitude of the third-order intermodulation product to the amplitude of the fundamental signal at a certain input amplitude. Definition of IP3: When the third-order intermodulation component increases to be equal to the fundamental frequency component, the receiver cannot receive normally, so there is a . Figure 7. Third-order Intermodulation Blocking Point 🔺Sideband Signals Figure 8. Sideband Signals and the Spectrum In fact, most of the sideband signals are generated outside the bandwidth after the useful signals of different frequencies within the bandwidth are modulated with each other. That is, the sideband signal rises faster than the in-band signal, and the spectral mask in the above figure becomes more and more flat. The increase of sideband signals will cause interference to adjacent channels, so the IEEE 802.11 protocol has strict requirements on the spectrum template, as shown in the Figure 9. Figure 9. DSSS Signal Modulation Spectral Mask Figure 10. OFDM 20MHz Bandwidth Signal Spectral Mask For the power amplifier, its nonlinear characteristics will increase the sideband of the modulated signal, and the sideband amplitude is not easily suppressed by other networks such as filters, and it is easy to cause design difficulties. Therefore, when choosing a PA, not only should pay attention to the maximum linear output that it can achieve, but also whether it can meet the sideband spectrum requirements at this output power.🔺Other Effects of NonlinearityIn addition to the previously mentioned gain drop, which generates a large number of harmonic components, as well as third-order intermodulation and sidebands, nonlinearity can also cause signal and EVM to deteriorate, etc. Ⅴ FAQ 1. What is RF power amplifier?A radio frequency power amplifier (RF power amplifier) is a type of electronic amplifier that converts a low-power radio-frequency signal into a higher power signal. 2. How does RF power amplifier work?An RF amplifier is actually a tuned amplifier that enables the input signal of broadcast or transmitted information to control an output signal. The RF amplifier uses frequency-determining networks to convert the input signal into an output signal that will provide the required response at a given frequency. 3. What is the most efficient class of RF power amplifier?Class C AmplifierThe Class C Amplifier design has the greatest efficiency but the poorest linearity of the classes of amplifiers mentioned here. The previous classes, A, B and AB are considered linear amplifiers, as the output signals amplitude and phase are linearly related to the input signals amplitude and phase. 4. How do I choose an RF power amplifier?Considerations When Choosing An RF Power Amplifier:Gain.Operating Frequency.Output Power Level.Efficiency.Linearity.Mismatch Tolerance.Noise Level. 5. What are the advantages of RF amplifier?Following are the RF Amplifier advantages:The RF amplifier offers greater gain i.e. better sensitivity. It offers better selectivity and hence it has ability to select wanted signals from multiple input signals at the RF receiver. 6. What are the different types of RF amplifiers?Amplifier TypesBroadband AmplifiersGain Block AmplifiersLog AmplifiersVariable Gain AmplifiersLow Noise AmplifiersCoaxial and Waveguide Power AmplifiersLinear AmplifiersBi-Directional Amplifiers 7. What is RF amplifier circuit?A radio frequency power amplifier (RF power amplifier) is a type of electronic circuit that converts a low-power radio-frequency signal into a higher power signal. 8. Is Class D amplifier better than a class AB?The most common audio power amplifier operates in the Class-AB mode. It provides the greatest amount of output power with the least amount of distortion. ... Class-D amplifiers are switches that are more efficient and produce less heat than their Class-AB equivalents. 9. What are RF amplifiers used for?Whenever people need to magnify a radio frequency signal into a higher power signal, the RF amplifier plays a pivotal role. They are used in commercial and defense avionics, space and deep space, electronic warfare, naval applications, mobile internet, satellite communication, and wireless communications. 10. Which amplifier is used in RF amplifier?RF power amplifiers using LDMOS (laterally diffused MOSFET) are the most widely used power semiconductor devices in wireless telecommunication networks, particularly mobile networks. LDMOS-based RF power amplifiers are widely used in digital mobile networks such as 2G, 3G, and 4G.
Ivy On 2022-02-16
ⅠIntroduction This project mainly introduces how to DIY a Simple Audio Player with Amplifier LM386 . But before this project, it is very essential to know some basics of LM386. Therefore, the first of this article is about LM386 audio amplifiers and the second part we will have a look at the practical appliance of Simple Audio Player with Amplifier LM386. Catalog ⅠIntroduction Ⅱ Amplifier LM386 Related Video: Ⅲ LM386 Basics 3.1 LM386 Datasheet 3.2 LM386 Pinout 3.3 LM386 Features Ⅳ Project Introduction 4.1 Hardware Required 4.2 Getting Ready with Your WAV Audio Files: 4.3 Circuit 4.4 Code 4.5 Working of this Arduino Music Player: Ⅴ FAQ How to make an LM386 audio amplifier circuit Amplifier LM386 Video Description: In this Video, We will explore how to use the popular LM386 class AB audio amplifier IC to build a simple mono 1 watt audio amplifier. Ⅲ LM386 Basics Despite the fact that LM386 audio amplifiers are quite old. They do, however, have a lot of useful information. Assume your audio player has poor sound quality. You want to boost the volume. They are a good option. Because of the low voltage supply and the fact that it works well with a battery. 3.1 LM386 Datasheet You completed an audio circuit . However, the sound is too faint. Many people use the LM386 to boost the sound to a speaker. The LM386 is a low-power audio amplifier. Also, you should be able to work with a battery, It has a similar shape to IC-741 and DIP-8. So, small and simple. Even if it's small, it makes a big sound. But...better. it's If you have previously read the LM386 Datasheet. 3.2 LM386 Pinout Figure1:pinout In DIP-8, we frequently use the LM386. There are only a few pin connections. Other packets are also the same. For example, SOP-8, TSSOP-8, and so on. 3.3 LM386 Features Ⅳ Project Introduction Including sounds or music in our project will always make it look and sound much more appealing. If you're working with an Arduino and have a lot of free spins, you can easily add sound effects to your project by purchasing an extra SD card module and a standard speaker. In this article, I'll show you how to play music and add sound effects with your Arduino board, as well as introduce the IC LM386 Amplifier , which we'll use in this process. We will play the.wav music files stored on an SD card in this project. The Arduino will be programmed to read these.wav files and play the audio on a speak through an LM386 Audio amplifier. Figure2: Project 4.1 Hardware Required Arduino Due Board8-ohm speaker or headphonesArduino shield with an SD card with cs CS 4 (like the Ethernet shield)Components to build an external audio amplifierLM386 (low power audio amplifier)10 kohm potentiometer10 ohm resistor2 x 10 µF capacitor0.05 µF (or 0.1 µF) capacitor250 µF capacitor 4.2 Getting Ready with Your WAV Audio Files: The audio file to be stored on the SD card must be in.wav format and have 44100 Hz, 16-bit stereo quality. We need audio files in.wav format to play sounds from an SD card using Arduino because the Arduino Board can only play audio files in a specific format, which is wav format. There are many mp3 shields available for use with Arduino to create an Arduino mp3 player. Alternatively, to play mp3 files in Arduino, there are websites that will convert any audio file on your computer into that specific WAV file. 4.3 Circuit The shield is placed on top of the Due, and a micro-SD card is inserted into the slot. The card's root directory contains a.wav file called "test.wav." For a quick test, connect a pair of headphones to the ground and DAC0 while keeping the polarity in mind. To add a speaker to the board, connect an amplification circuit between the DAC0 pin and the speaker. The amplification circuit will boost the speaker's volume, There are numerous audio amplifiers available, with the LM386 being one of the most common. The following scheme demonstrates how to construct the circuit using the LM386 and a variety of components. You can power the LM386 by connecting the Vs pin to various voltage sources, such as the +5 V on the Arduino Due's 5V pin or an external 9V battery, The capacitor is connected to pins 1 and 8 of the LM386 provides the amplifier's gain. The gain is set to 200 with the 10 F capacitor, and 50 without the capacitor. The volume of the amplifier can be adjusted using the potentiometer. Caution: Do not connect the speaker directly to the Arduino Due's pins. Figure3 : Circuit Figure4: LM386 mounting on breadboard 4.4 Code 4.5 Working of this Arduino Music Player: Simply press the button connected to pin 2 after programming your Arduino, and your Arduino will play the first song (saved as 1.wav) for you. You can now press the button again to change your track to the next song, 2.wav. Similarly, you can listen to all four songs. You can also play/pause the song by pressing the pin 3 button. Press it once to pause the song and once more to resume it from where it left off. Watch the video below to see the entire process in action (or maybe to relax with some songs). I hope you had a good time with the project. It is now up to your imagination to incorporate them into your projects. You can create a speaking clock, voice assistant, talking robot, voice alert security system, and many other things. Ⅴ FAQ 1. How many watts is LM386? 700mW, mono, 5- to 18-V, analog input Class-AB audio amplifier. 2. How do you calculate LM386 gain? Voltage Gain Analysis: Without any external components, it has a gain of Gv = 2x15K/(150+1350) = 20 (26 dB). With a capacitor (or shortcutting) between pins 1 and 8 , it has a gain of Gv = 2x15K/150 =200 (46dB). 3. Is LM386 any good? The LM386 is a well-designed, basic workhorse that does a decent job when its hooves are kept clean and it's well-fed. Aside from having a slow op-amp stage by today's standards, it has decent performance. It can also sound horrible if you neglect it. 4. What is an audio amplifier circuit? The circuit of the audio amplifier consists of a transistor a device to apply the input signals and a speaker at the output. The transistors are connected based on the necessity. The important factors that need to be considered while designing a audio amplifier is gain,noise, frequency response and distortion. 5. Which amplifier can be used for audio amplifier? An audio power amplifier (or power amp) is an electronic amplifier that amplifies low-power electronic audio signals such as the signal from radio receiver or electric guitar pickup to a level that is high enough for driving loudspeakers or headphones. 6. What is the need of power amplifier? The function of a power amplifier is to raise the power level of input signal. It is required to deliver a large amount of power and has to handle large current. The characteristics of a power amplifier are as follows − The base of transistor is made thicken to handle large currents.
kynix On 2021-12-24
Introduction Operational amplifiers will oscillate in many practical applications. For example, there are many kinds of loads that will cause them to oscillate. A feedback network that is not properly designed can cause them to become unstable. Insufficient power supply bypass capacitors may also make them unstable. Even the input and output may oscillate into a single-port system. This article will tell some common causes that cause the op amp to oscillate and the corresponding countermeasures. Catalog Introduction Ⅰ Basic Op Amp Circuits Ⅱ Example: LTC6268 Amplifier Ⅲ Decompensated Amplifiers Ⅳ Feedback Network Ⅴ Load Problem Ⅵ Strange Impedance Ⅶ Power Ⅷ Conclusion Ⅸ FAQ Ⅰ Basic Op Amp Circuits Figure 1. shows a block diagram of a non-rail-to-rail amplifier. The input controls the gm box, which drives the gain node and is buffered at the output. The compensation capacitor Cc is the main frequency response component. The return pin of Cc should be grounded, if there is such a pin and the op amp is not grounded, the capacitor current will return to one or two power supplies. Figure 1. Block Diagram of a Non-Rail-to-Rail Amplifier Figure 2. is a block diagram of a rail-to-rail output amplifier. The output current of the input box gm is sent through a current coupler, which divides the current into two parts and supplies them to the output transistor. The frequency response is determined by two Cc/2s, which are actually connected in parallel. Figure 2. Block Diagram of a Rail-to-Rail Output Amplifier Figure 3. shows the frequency response of the ideal amplifier. Although the electrical principles of the two circuits are different, the behavior is similar. The single pole compensation formed by gm and Cc provides a unity gain bandwidth product frequency of GBF = gm/(2πCc). In the vicinity of GBF/Avol, the phase lag of these amplifiers changes from -180° to -270°, where Avol is the open-loop DC gain of the amplifier. When the frequency is much higher than this low frequency, the phase stays at –270°. This is the well-known "dominant pole compensation", where the Cc dominates the frequency response, hiding the various frequency limitations of the active circuit. Figure 3. Frequency Response of the Ideal Amplifier Ⅱ Example: LTC6268 Amplifier Figure 4. shows the open-loop gain and phase response of the LTC6268 amplifier with frequency. The LTC6268 is a small and low-noise 500MHz amplifier with rail-to-rail output and only 3fA bias current. It can be used as a good example to illustrate the performance of real amplifiers. The -90° phase lag of the dominant pole compensation starts from about 0.1MHz, reaches -270° around 8MHz, and moves down by more than -270° when it exceeds 30MHz. In fact, all amplifiers have high frequency phase lag, except for the basic dominant compensation lag caused by the additional gain stage and output stage. Generally, the starting point of the additional phase lag is around GBF/10. Figure 4. Open-Loop Gain and Phase Response of the LTC6268 Amplifier with Frequency The stability of the feedback is a matter of loop gain and phase, or Avol multiplied by the feedback coefficient, which is the loop gain. If we connect the LTC6268 in a unity gain configuration, 100% of the output voltage is fed back. At very low frequencies, the output is the negative value of the "–" input, or the phase lags by -180°. Compensation adds a -90° hysteresis through the amplifier, introducing a –270° hysteresis from the "–" input to the output. When the loop phase lag increases to ±360° or its multiples, oscillation will occur, and the loop gain is at least 1V/V or 0dB. The phase margin is a measure of how much the phase lag differs from 360° when the gain is 1V/V or 0dB. Figure 4. shows that the phase margin is about 70° (10pF red curve) at 130MHz, and the phase margin as low as about 35° is feasible.A topic that is not often mentioned is gain margin, although it is an equally important parameter. When it is reduced to zero at some higher frequencies, the amplifier will oscillate if the gain is at least 1V/V or 0dB. As shown in Figure 4, when the phase drops to 0° (or a multiple of 360°, or –180° as shown in the figure), the gain is about –24dB around 1GHz. This is a very low gain and no oscillations will occur at this frequency. In fact, people want the gain margin to be at least 4dB. Ⅲ Decompensated Amplifiers Although the LTC6268 is fairly stable at unity gain, there are still unstable op amps. By designing the amplifier compensation to be stable only at higher closed-loop gains, the design trade-off can provide a higher conversion rate, wider GBF, and lower input noise than the unity gain compensation scheme. Figure 5. shows the open loop gain and phase of the LTC6230-10. The amplifier is intended to be used with a feedback gain of 10 or greater, so the feedback network will attenuate the output by at least 10 times. Through this feedback network, you can find the frequency when the open-loop gain is 10V/V or 20dB, and find that the phase margin is 58° at 50MHz (±5V power supply). At unity gain, the phase margin is only about 0°, so the amplifier oscillates. Figure 5. LT6230-10 Gain and Phase Change with Frequency It is observed that when the closed-loop gain is higher than the minimum stable gain, all amplifiers will be more stable. Even a gain of 1.5 will make a unity gain stable amplifier much more stable. Ⅳ Feedback Network The feedback network itself may also cause oscillations. In Figure 6, put a parasitic capacitor in parallel with the feedback divider resistor. It is inevitable that each terminal of each component on the circuit board has a capacitance of about 0.5pF to the ground, and there is also a wiring capacitance. Figure 6. Parasitic Capacitance In fact, the minimum capacitance of the node is 2pF, and there is about 2pF of wiring capacitance per inch of trace. The accumulated parasitic capacitance can easily reach 5pF. Using LTC6268, in order to reduce the power, we set the values of Rf and Rg to a very high 10kΩ. When Cpar = 4pF, the feedback network has a pole at 1/(2π*Rf||Rg*Cpar) or 8MHz. The phase lag of the feedback network is -atan(f/8MHz), we can estimate that the loop will have a phase lag of 360° around 35MHz. At this time, the phase lag of the amplifier is -261°, and the feedback network lags about -79°. At this phase and frequency, the amplifier still has a gain of 22dB, and the gain of the voltage divider is .At the 0° phase, the amplifier's 22dB multiplied by the feedback divider's –19dB produces a +3dB loop gain, and the circuit oscillates. In order to operate normally in the presence of parasitic capacitance, we must reduce the value of the feedback resistor so that the feedback pole can far exceed the unity gain frequency of the loop. That is, the ratio of the pole to the GBF should be at least 6 times.The input end of the op amp itself may also have a considerable capacitance, the same as Cpar. In particular, low noise and low Vos amplifiers have large input transistors and may have larger input capacitance than other types of amplifiers, and the input capacitance is loaded on the amplifier's feedback network. We need to consult the data sheet to understand how much capacitance will be connected in parallel with Cpar. Fortunately, the LT6268 has only 0.45pF capacitance, which is already very low for such a low noise amplifier. The macro model running on LTspice® provided free of charge by ADI can be used to simulate a circuit with parasitic capacitance. Figure 7. shows how to improve the capacitor tolerance of the voltage divider. Figure 7(a) shows a non-negative output amplifier configuration with Rin. Assuming that Vin is a low impedance source (<Rin), Rin will effectively attenuate the feedback signal without changing the closed-loop gain. And it will also reduce the impedance of the voltage divider and increase the feedback pole frequency, which is expected to far exceed GBF. In addition, Rin reduces the bandwidth around the loop and amplifies the input offset and noise.Figure 7(b) shows a negative output configuration. Rg still performs loop attenuation without changing the closed loop gain. In this case, the input impedance is not affected by Rg, but the noise, offset and bandwidth parameters will deteriorate.Figure 7(c) shows the preferred method of compensating Cpar in a non-inverting amplifier. If we set Cf* Rf = Cpar * Rg, then we have a "compensation attenuator", so that the feedback divider now has the same attenuation at all frequencies and solves the Cpar problem. The mismatch in the product will cause "bumps" in the passband of the amplifier and "shelf" in the response curve (At this time, the low-frequency response is flat, but becomes straight near f = 1/2 * Cpar * Rg.).Figure 7(d) shows the equivalent Cpar compensation for the negative output amplifier. The frequency response must be analyzed to find a correct Cf, and the bandwidth of the amplifier is part of the analysis.Here are some comments on current feedback amplifiers (CFA) in turn. If the amplifier in Figure 7(a) is a CFA, then "Rin" has little effect on changing the frequency response, because the negative input is very low impedance and actively copies the positive input. The noise index will degrade slightly, and the additional negative input bias current will actually appear in the form of Vos/Rin. Similarly, in terms of frequency response, the circuit in Figure (b) is not changed by "Rg". The inverting input is not just a virtual ground, it is a real ground with low impedance, and Cpar has been tolerated (only in negative output mode). The DC error is similar to the situation shown in (a), (c) and (d) may be the preferred solution for voltage input op amps, but CFA can't tolerate a direct feedback capacitor without oscillation at all. Ⅴ Load Problem Just as the feedback capacitor can damage the phase margin, the load capacitor can do the same. Figure 8 shows the change in LTC6268 output impedance with frequency in the case of several gain settings. Note that the unity gain output impedance is lower than the output impedance at higher gains. Full feedback enables the open-loop gain to reduce the inherent output impedance of the amplifier. Therefore, in Figure 8, the output impedance at a gain of 10 is generally 10 times the output impedance at unity gain. Since the feedback attenuator reduces the loop gain, the gain around the loop is 1/10, otherwise it will reduce the closed-loop output impedance. The open-loop output impedance is about 30, which is obvious in the high-frequency flat region of the curve with a gain of 100. In this area, from around gain bandwidth frequency (about 100) to gain bandwidth frequency, there is not enough loop gain to reduce the open loop output impedance. Figure 8. Impedance and Frequency of LTC6268 Under Three Gain Conditions The capacitor load will cause the phase lag and amplitude attenuation of the open-loop output impedance. For example, a 50pF load and our LTC6268 output impedance form another pole at 106MHz, where the output has a –45° phase lag and –3dB attenuation. At this frequency, the amplifier has a phase of -295° and a gain of 10dB. Assuming unity gain feedback is used, we have not fully realized the oscillation because the phase is not brought to ±360° (at 106MHz). However, at 150MHz, the amplifier has 305° phase lag and 5dB gain. The phase of the output pole is –atan(150MHz/106MHz) = -55°, and the gain is .Multiplying the gain cyclically, we get a 360° phase and +0.2dB gain, which is another oscillator. 50pF seems to be the minimum load capacitance that will force the LTC6268 to oscillate.The most common way to prevent oscillations caused by the load capacitor is to simply connect a small resistor in series to the capacitor after the feedback connection. The resistance value of 10Ω to 50Ω will limit the phase lag that may be caused by the capacitive load and isolate the amplifier and low capacitive impedance when the speed is very high. Disadvantages include DC and low frequency errors that vary with load resistance characteristics, capacitive load frequency response is limited, and signal distortion caused if the load capacitance is not constant when the voltage changes.Increasing the closed-loop gain of the amplifier can often prevent the oscillation caused by the load capacitance. Operating the amplifier with a higher closed-loop gain means that at frequencies where the loop phase is ±360°, the feedback attenuator also attenuates the loop gain. For example, if we use the LTC6268, its closed-loop gain is +10, then we will see that the amplifier has a gain of 10V/V or 20dB at 40MHz and a phase lag of 285°. To ignite the oscillation, an output pole is required, causing an additional 75° hysteresis. By -75° =-atan(40MHz/Fpole) →Fpole =10.6MHz, we can find the output pole. This pole frequency comes from a load capacitance of 500pF and an output impedance of 30Ω. The output pole gain is .When the unloaded open-loop gain is 10, the loop gain at the oscillation frequency point is 0.26, so there is no oscillation this time, at least no oscillation caused by the simple output pole. In this way, we increased the tolerable load capacitance from 50pF to 500pF by increasing the closed-loop gain.In addition, unterminated transmission lines are also very bad loads because they will cause "runaway" impedance and phase changes that repeat with frequency (See the impedance of an unterminated 9-foot cable in Figure 9).If your amplifier can safely drive the cable under certain low-frequency resonance conditions, it is likely to oscillate at a higher frequency because its own phase margin is reduced. If the cable must be unterminated, a "back-match" resistor in series with the output can isolate the cable's extreme impedance changes. In addition, even if the transient reflection from the this end of the cable just recoils back to the amplifier, if the resistance of the backward matching resistor matches the characteristic impedance of the cable, the resistor can properly absorb this energy. If the backward resistor does not match the cable impedance, some energy will be reflected from the amplifier and terminals, and back to the unterminated end. When the energy reaches this end, it is quickly reflected back to the amplifier. As a result, there is a series of pulses bouncing back and forth, but attenuate each time. Figure 9. Impedance and Phase of the Unterminated Coaxial Cable Figure 9 shows a more complete output impedance model. The ROUT is the same as what we discussed in the LTC6268, and it is also 30Ω, in addition, add the Lout item. This is a combination of physical inductance and electronic equivalent inductance. The physical package, bonding wire, and external inductance add up to 5nH to 15nH. The smaller the package, the smaller the total value. Figure 10. Inductive Component of Amplifier Output Impedance In addition, any amplifier has an electrical inductance of 20nH to 70nH, especially bipolar devices. The finite Ft of the device turns the parasitic base resistance of the output transistor into an inductance. The harm is that Lout and CL may interact to form a series resonant circuit, then the same problem comes again. If there is no greater phase lag in the loop, the impedance of the series resonant circuit may drop to a level that Rout cannot drive. This may cause oscillations. For example, set Lout = 60nH and CL = 50pF. Resonant frequency is .Just within the passband of the LTC6268. In fact, this series resonant circuit is loaded to the output terminal during resonance, which changes the phase of the loop greatly near the resonant frequency. Unfortunately, Lout is not mentioned in the amplifier's data sheet, but its effect can sometimes be seen on the open-loop output impedance circuit. In short, for amplifiers with a bandwidth of less than 50MHz, this effect is not important.One solution is shown in Figure 10. Rsnub and Csnub form a so-called "shock absorber" whose purpose is to reduce the Q value of the resonant circuit so that the resonant circuit does not have a very low resonant impedance to the output of the amplifier. The value of Rsnub is usually estimated as the reactance of CL to reduce the Q value of the output resonance circuit to about 1. Adjust the size of Csnub to fully insert Rsnub into the output resonance frequency, that is, the reactance of Csnub <Cl. Csnub = 10 * CL is practical. Csnub unloads the amplifier at intermediate and low frequencies, especially at DC. If it is very large, Rsnub will put a heavy load on the amplifier at intermediate frequency, which will affect the low frequency, gain accuracy, closed-loop bandwidth and distortion. However, after a little fine-tuning, shock absorbers are often useful for controlling reactive loads, but shock absorbers must be adjusted through experiments. Figure 11: Using an Output Shock Absorber The negative input of the current feedback amplifier is actually a buffer output and will also have the series characteristics shown in Figure 8. Therefore, it may oscillate under the action of Cpar, just like the output terminal. You should try to reduce Cpar and any related inductance. Unfortunately, the damper on the negative input terminal modifies the relationship between closed-loop gain and frequency, so it is not very useful. Ⅵ Strange Impedance Many amplifiers have an abnormal input impedance at high frequencies. This is most true for amplifiers with two input transistors in series, such as the Darlington configuration. Many amplifiers have PNP/NPN transistor pairs at the input, and their behavior changes with frequency similar to the Darlington configuration. The real part of the input impedance will become negative at some frequencies (generally much higher than GBF). Inductive source impedance will resonate with the input and circuit board capacitance, and negative real components may provoke oscillations. When driving with unterminated cables, this can also cause oscillations at many repetition frequencies. If it is inevitable to use a long inductive wire at the input, you can disconnect the wire with several series-connected resistors that can absorb energy, or install a medium-impedance shock absorber (about 300Ω) on the input lead of the amplifier. Ⅶ Power The last source of oscillation to consider is power supply bypass. Figure 10 shows part of the output circuit. LVS+ and LVS– are the unavoidable packaging, IC bond wires, the physical length of the bypass capacitor (inductive like any conductor), and the series inductance of the circuit board traces. It also includes the external inductance that connects the local bypass component to the rest of the power bus (if not the power plane). Although 3nH to 10nH may seem small, at 200MHz, it is 3.8 to 12Ω. If the output transistor conducts a large high-frequency output current, there will be a voltage drop across the power inductor. Figure 12. Power Supply Bypass Capacitor Details The rest of the amplifier needs a noise-free power supply, because these parts cannot suppress power supply noise as the frequency changes. In Figure 13 we can see the power supply rejection ratio (PSRR) of the LTC6268 with frequency. In all operational amplifiers, because there is no ground pin, the compensation capacitor is connected to the power supply, which will couple power supply noise into the amplifier, and gm must cancel this noise. Due to the compensation, PSRR decreases with 1/f, in addition, the power supply rejection actually increases after 130MHz. Figure 13. LTC6268 Power Supply Rejection with Frequency Variation At 200MHz, due to the increase of PSRR, the output current may interfere with the power supply voltage inside the LVs inductor. Through the amplification of PSRR, the interference becomes a strong amplifier signal, driving the output current, generating internal power signals, etc., causing the amplifier to oscillate. This is why the power supplies of all amplifiers must be carefully bypassed with traces and components with very small inductance. In addition, the power supply bypass capacitor must be much larger than any load capacitor.If consider the frequency around 500MHz, then the range 3nH to 10nH becomes 9.4Ω to 31.4Ω. This is enough for the output transistor to generate self-oscillation by its inductance and IC component capacitance, especially when the output current is large (transistor gm and bandwidth increase). Because the bandwidth of transistors is very large, special attention needs to be paid, especially at high output currents. Ⅷ Conclusion In short, the designer needs to consider the parasitic capacitance and inductance associated with each op amp terminal and the natural characteristics of the load. Usually the designed amplifier is very stable in the nominal environment, but each application needs to analyze it by itself. Ⅸ FAQ 1. Does your op amp oscillate?Well, it shouldn't. We analog designers take great pains to make our amplifiers stable when we design them, but there are many situations that cause them to oscillate in the real world. ... Improperly designed feedback networks can cause instability. Insufficient supply bypassing can offend. 2. What is oscillator in op amp?An oscillator is an electronic circuit that produces a periodic signal. ... The feedback network takes a part of the output of amplifier as an input to it and produces a voltage signal. This voltage signal is applied as an input to the amplifier. 3. What causes an amplifier to oscillate?Causes of parasitic oscillationParasitic oscillation in an amplifier stage occurs when part of the output energy is coupled into the input, with the correct phase and amplitude to provide positive feedback at some frequency. ... Similarly, impedance in the power supply can couple input to output and cause oscillation. 4. How do you compensate an op amp?Another effective compensation technique is the miller compensation technique and it is an in-loop compensation technique where a simple capacitor is used with or without load isolation resistor (Nulling resistor). That means a capacitor is connected in the feedback loop to compensate the op-amp frequency response. 5. How can an op amp improve stability?To ensure stability, the value of RX should be such that the added zero (fZ) is at least a decade below the closed loop bandwidth of the op amp circuit. With the addition of RX,circuit performance will not suffer the increased output noise of the first method, but the output impedance as seen by the load will increase. 6. What are the requirements of oscillations in an amplifier?Oscillations around the 3dB bandwidth of the amplifier are usually due to input/output feedback. Higher frequency oscillations may only be visible on a spectrum analyzer. They may cause waveform distortion and be affected by touching the amplifier on power and signal cables. 7. How do you stop an oscillating op amp?If the op-amp still oscillates, try these things, in this order:1) Add a small resistor to the op-amp's output, either inside or outside the feedback loop. ...2) Do the same as in the previous step, except use a ferrite bead or chip ferrite instead of the resistor. ...3) Raise the amp's gain a bit. 8. How do you increase the gain margin of an op amp?You can increase the phase margin by making a dominant pole nearer to the zero frequency origin. This is accomplished by compensating the op amp through adding a shunting capacitor in the highest impedance node of the amplifier. This is a very well known technique which is used commonly to increase the phase margin. 9. Why the gain of op amp deteriorate with frequency?All opamps have a limit on upper frequency. In a LPF, at low frequencies, the output amplitude is equal to input. But as the frequency increases, the capacitive reactance decreases and the output amplitude starts to decrease. 10. What is used to avoid or minimize instability in amplifiers?It is often desirable to use capacitance to ground from an amplifier's active input terminals to reduce high-frequency interference, RFI and EMI. This filter capacitor has a similar effect on op amp dynamics as increased stray capacitance. 11. Why op amps oscillate an intuitive look at two frequent causes?With delay in the loop, the amplifier does not immediately detect its progress toward the final value. ... It overreacts by racing too quickly toward the proper output voltage. Note the faster initial ramp rate with delayed feedback. 12. How does an op-amp oscillator work?The Op-amp Multivibrator is an astable oscillator circuit that generates a rectangular output waveform using an RC timing network connected to the inverting input of the operational amplifier and a voltage divider network connected to the other non-inverting input.
kynix On 2021-12-10
Introduction The transistor is a current-control device. For example, control the collector-emitter current by changing the base current. In a general voltage amplification occasion, this amplification effect comes from the use of resistors to convert current into voltage. In the small-signal model, the source of the base current is the ratio of the input voltage to the base-emitter dynamic resistance rbe, which is usually kΩ. So the base current is very small, and may only be a few tenths of mA. Through the amplification of the transistor, the base current is generated between the collector and the emitter by β times. This article will introduce how transistor works in the common-emitter amplifier circuit. Transistor Amplifiers Circuit Introduction Catalog Introduction Ⅰ Common-emitter Amplifier Circuit Formula Ⅱ Common-emitter Amplifier Circuit Design 2.1 Design Steps 2.2 Circuit Analysis 2.3 Common-emitter Circuit Design 2.4 Circuit Performance Parameters Ⅲ Common-emitter Amplifier Circuit Expansion 3.1 Increase Magnification 3.2 Low-voltage and Low-loss Circuit 3.3 Differential Output Circuit 3.4 Filter and Tuning Amplifier Circuit Ⅳ Summary Ⅴ FAQ Ⅰ Common-emitter Amplifier Circuit Formula Here, take the common emitter amplifier circuit as an example: Figure 1. Transistor Common-emitter Amplifier Circuit △Vo=VCC-△ieRc=VCC-β△ibRc=VCC-△Vi·Rc/rbe△Vi/rbe=△ibThus, the collector generates a current of β times ib:△ie=β△ibFurthermore, the output voltage can be obtained by the relative positive power supply potential:△Vo=VCC-△ieRc=VCC-β△ibRc=VCC-△Vi·Rc/rbeThus, we can get an inverted amplified voltage signal by AC coupling and controlling the collector resistance Re. But generally the emitter will have a resistance to control the gain, so the above formula is not practical. When designing a circuit in non-extreme situations, we often hope that the circuit can work with most general-purpose transistors, avoiding the parameter that depends on component parameters such as rbe. At the same time, it is very cumbersome to consider the base current in the specific calculation. Therefore, in the general design process, the existence of the base current is ignored in an approximate calculation (In some circuits, although the base current is ignored, it is still necessary to give the base a certain current drive to make the circuit working normally). In addition, the calculation of gain is the external circuit resistance not the rbe.Among them, the base-emitter tube voltage drop VBE is also a very important parameter, which is generally equal to 0.6V (silicon tube). The parameters of the transistor circuit can all be obtained according to VBE=0.6V and Ohm's law.The cumbersome part of the transistor circuit lies in the setting of the static operating point. Usually, careless design will cause clipping and distortion of the output waveform. Therefore, the selected values of some experimental values can be used for reference. The overall design idea is: quantitatively determine the voltage and current to calculate the resistance. Ⅱ Common-emitter Amplifier Circuit Design The common-emitter amplifier circuit is a typical inverting amplifier, which has a wide range of applications and stable effects. First show the overall design ideas, and then explain the purpose and principles of the design in steps. 2.1 Design Steps 1) Determine the supply voltage VCC, and determine the static emitter current IE according to the frequency curve/noise curve/others.2) Determine VE, where selects 1~2V to absorb temperature drift.3) According to VE and IE, calculate the emitter static resistance RE ( IE≈IC).4) Determine the magnification Av, and apply the relationship Av=RC/RE to calculate the static collector resistance RC. At this point, the static working point has been established.5) Check whether the static operating point meets the requirements: positive output swing limit=VCC-IE·RC, negative output swing limit=IE·RC-VE. It is necessary to ensure that the amplified output voltage does not exceed the swing limit (usually the swing limit is larger). If RC is too large, there will be a downside clipping, so is the small RC. In addition, determine whether the power exceeds the limit: PC=VCE·IC.6) Determine the base bias voltage as follows: According to VBE=0.6V, it is easy to get VB=VE+0.6 (divide the voltage from the power supply through the resistor). Since ib is considered to be small and negligible, the current IB0 flowing through the base voltage divider resistors (R1, R2 in the above figure) should be much larger than ib. ib is approximately calculated as IC/β, and IB0 is about an order of magnitude larger than ib, so R2=VB/IB0, R1=(VCC-VR2)/IB0.7) Finally, determine the AC coupling capacitor value and the power supply decoupling capacitor value.Let's first use a designed common-emitter amplifier circuit to intuitively understand the waveforms of the next parts: Figure 2. Transistor Common Emitter Amplifier Circuit Design As shown in the figure, the circuit uses 2SC2240 tube, 15V power supply, and the input and output are AC coupled. The output signals are as following: Figure 3. 4-channel Signal Waves The pale blue waveform is the input signal, selecting the sine wave of 1kHz, 1Vpp.The green is the output signal, amplified by about 5 times, and it is inverted.The blue is the base signal, which can be seen because the DC level is raised due to the influence of the base bias resistance.The red is the emitter signal, which is only a fixed value away from the base signal. 2.2 Circuit Analysis First, perform a DC analysis, that is, determine the static operating point. In the initial design process, the design and verification of static operating points are also the first to proceed. The static potential of the base can be easily calculated according to the base bias resistance, and the static potential of the emitter can be determined according to the voltage drop of the base-emitter tube as a constant. Therefore, according to the magnitude of the emitter resistance, the magnitude of the collector-emitter current can be obtained, and then the collector static potential can be obtained from the power supply voltage.Why is the static operating point important? Take the NPN transistor as an example, which is equivalent to two back-to-back diodes. If requiring the diode work, you must give it a proper bias to make it reasonably conductive. In the circuit, the base-collector diode prevents internal feedback, and the base-emitter diode is the key to achieving amplification. In other words, it is enough to design an external circuit so that the current flows normally in the base-emitter diode. This idea will be mentioned in the analysis of the carrying capacity of the emitter follower.Find the AC voltage gain. When the input voltage changes △vi, it will cause the emitter current to produce an AC change △ie. Since the base emitter voltage drop is constant, it does not contribute to the AC change, so △ie=vi/RE. Therefore, the emitter AC output voltage can be determined as vo=△ieRC=vi·RC/RE, and the AC gain is Av=RC/RE. This conclusion can quickly analyze the magnification of the common-emitter circuit.The output power rails are VCC and VE respectively, which are determined by the current characteristics of the transistor during operation, and there is generally no rail-to-rail output. According to the output power rail and the AC amplification factor, the circuit can be used.When the input and output are not AC coupled, the input (especially for DC) will cause the output waveform to be distorted. 2.3 Common-emitter Circuit Design After understanding the circuit characteristics, you can design the common emitter circuit according to the design steps at the beginning of this section. The static operating point and magnification have been determined during the analysis, and the other parts are designed below.Supply voltage: According to the swing of the output voltage, we can determine the size of the voltage. Usually the power supply voltage is larger than the output peak-to-peak value.Transistor: Select the appropriate transistor according to the operating frequency, required power, noise level and β, etc.Emitter current: Determine the size of the emitter current according to the frequency characteristics by consulting the device manual.RC and RE: Determined by the emitter voltage and current, and the magnification, pay attention to review the upper and lower limits of the swing and the rated power.Base bias resistance: VB is determined according to VE, thereby determining the voltage divider resistance of the power supply. Note that the current flowing through the voltage divider resistor should be one to two orders of magnitude higher than the base current. The base current is calculated by dividing the collector-emitter current by β.Coupling capacitor: The AC coupling capacitor is generally 10uF. Note that the coupling capacitor of the output stage and the input impedance of the next stage will form a high-pass filter. The cutoff frequency of the filter should be handled carefully. 2.4 Circuit Performance Parameters Through the method of AC analysis, we can obtain some characteristic parameters of the designed circuit, such as input and output impedance, magnification and so on.Input impedance: According to AC analysis, the input impedance is the parallel value of the base bias resistance. In small signal analysis, the base emitter dynamic resistance rbe should also be connected in parallel.Output impedance: The method to determine the output impedance is to add a load to the circuit. When the peak-to-peak output value drops to half of the no-load, the load impedance is the output value. Generally, the output impedance of the common-emitter amplifier circuit is the collector resistance RC.Magnification: Due to the influence of the base current, the actual magnification is about 10% lower than the design value. So the design formula is more practical. Ⅲ Common-emitter Amplifier Circuit Expansion By improving the general common-emitter amplifier circuit, various application circuits with other characteristics can be obtained. This section introduces the means to increase the magnification, the low-voltage power supply circuit, the differential output circuit, and the tuning amplifier circuit. 3.1 Increase Magnification According to the introduction of the design circuit, the voltage gain is mainly determined by the ratio of the collector resistance RC to the emitter resistance RE. So it is common to change the ratio of the resistance to change the gain. However, the problem arises: these two resistors are responsible for determining the working current at the same time. Because the DC operating point is changed arbitrarily, the circuit is likely to be distorted or even not work.From another perspective, voltage gain belongs to the category of "AC Analysis", and the static operating point belongs to "DC Analysis". So add some reactive components to the circuit to change the ratio under the AC perspective, the resistance value during DC analysis does not change.This can be achieved by connecting the emitter resistor in parallel, or making the resistor in parallel with the capacitor, that is, modifying the circuit in the first section: Figure 4. Common-emitter Amplifier Circuit Pay attention to the emitter in the above figure. In the AC analysis, the resistor R4 is short-circuited by the capacitor. At this time, it is equivalently considered that the emitter resistor is only R7 (330Ω). From the signal source and the oscilloscope, the signal has been amplified nearly 50 times at this time. It is much larger than the original design value (10k/2k=5), thus realizing the expansion of voltage gain. If the original emitter resistance is not split, but the entire capacitor is connected in parallel, the maximum gain βRC/rbe will be obtained at this time.How to choose the capacitance value? It should be noted that after the capacitors are connected in parallel, the entire circuit will have high-pass characteristics, and the cut-off frequency is f=1/2πRC. If this high-pass characteristic is not required, the C capacitance value can be selected to a larger value between 47uF~100uF.In addition, the capacitor C6 has the function of temperature compensation. 3.2 Low-voltage and Low-loss Circuit If the op amp circuit is powered by a dry battery (1.5V), it is not realistic, but the transistor circuit can be done. The key is to use the conduction voltage drop of the external diode to offset the base-emitter voltage and have small small. The circuit in the figure below can still amplify small signals as designed even under 1.5V power supply: Figure 5. Common-emitter Amplifier Circuit But the disadvantage is that the maximum voltage of the system is always below the supply voltage. Because of the small circuit loss, it is suitable for low power consumption. 3.3 Differential Output Circuit Fully differential op amps can provide dual-mode output, and many transmission lines also require differential transmission. Transistor circuits can also perform differential output. In addition to the principle of a common emitter amplifier circuit, the principle of an emitter follower is also used. The following figure shows the circuit connection of the differential output. Figure 6. Common-emitter Amplifier Circuit It can be seen that two differential signals with the same shape and opposite phase are output. The collector signal is in phase with the input signal, and the emitter output signal is in phase with the input signal. However, the output impedance of the two signals is different due to the different lead-out positions. The output impedance of the inverted output is higher (RC), and the output impedance of the non-inverted output is lower, which is suitable for driving the load. The inverted output is generally connected to the emitter follower before driving.In addition, the static potential of the base should be set between VCC and GND as much as possible to expand the undistorted output range. 3.4 Filter and Tuning Amplifier Circuit The introduction of reactive components in the circuit will cause the properties of the circuit to change with the frequency. We can use this property to design LPF, HPF, and tuning amplifier commonly used in high-frequency circuits. Actually, it uses the characteristic that the impedance of the reactance element changes with the frequency, and then changes the voltage gain at the current frequency. The impedance at the resonance frequency is often purely resistive and has an extreme value to achieve frequency selective amplification. The following show low-pass, high-pass and frequency selective amplifiers at specific frequencies:① LPF Figure 7. Common-emitter Amplifier Circuit As shown in the figure, a low-pass filter is constructed (the input of the bode tester is placed at the base instead of the output of the signal generator, because the input coupling capacitor will form a high-pass filter with the input resistor, which affects the observation effect), and its cut-off frequency is about 1.06kHz, calculated by f=1/2πRcC.From the sinusoidal steady-state analysis, the impedance of the RC parallel loop is R/√(1+(wRC)^2). As the frequency increases, the impedance decreases, so the voltage gain decreases, forming a low-pass characteristic.② HPF Figure 8. Common-emitter Amplifier Circuit As shown in the figure, a high-pass filter is constructed, and the calculation of its cut-off frequency is similar to that of LPF.At the gain peak point, the voltage gain reaches 50dB, which is close to the β value of the transistor. Then the gain is attenuated due to the deterioration of the transistor's frequency characteristics.③ 10.7MHz Figure 9. Common-emitter Amplifier Circuit By replacing RC with an LC network with a resonance frequency of 10.7MHz, a frequency selective amplifier can be obtained. As shown in the figure, the amplification factor is 35dB at 10.7M, while the amplification factor when detuning 1MHz is only 12.6dB. The disadvantage is that the pass-band is slightly wider, the rectangular coefficient is not good enough, and the equivalent quality factor of the loop is about 65.2, which is relatively large. In addition, the high-frequency decoupling capacitor has been changed to 1uF. Resonant Amplifier Circuit Example: Figure 10. Resonant Amplifier Circuit Example Ⅳ Summary Transistor amplifier circuit is the basis of an operational amplifier circuit, and common-emitter configuration is the most commonly used form. Drawing lessons from the feature that the amplifier's magnification can be easily determined by the ratio of two resistors, and the gain of the common emitter amplifier can also be approximated by the ratio of the two resistors. Ⅴ FAQ 1. What are transistor amplifiers used for?Amplifiers are derived from the transistors because they are capable of operating under three regions active, cut-off and saturation. For the purpose of amplification, the focus will be on the active region. The main purpose of these amplifiers is to enhance the strength of the applied input signal without alteration. 2. How does a transistor amplify current?Transistors are normally used as amplifiers. ... The small current travels from the voltage source into the base of the transistor. A current at the base turns on the transistor. The current is then amplified and travels from the emitter of the transistor to the collector. 3. What is a common emitter transistor amplifier?The common emitter amplifier is a three basic single-stage bipolar junction transistor and is used as a voltage amplifier. The input of this amplifier is taken from the base terminal, the output is collected from the collector terminal and the emitter terminal is common for both the terminals. 4. Why common emitter is used in amplifier?Common emitter (CE) configuration. ... Common emitter transistors are used most widely, because a common emitter transistor amplifier provides high current gain, high voltage gain and high power gain. This type of transistor gives for a small change in input there is small change in output. 5. What is the use of CE amplifier?In electronics, a common-emitter amplifier is one of three basic single-stage bipolar-junction-transistor (BJT) amplifier topologies, typically used as a voltage amplifier. It offers high current gain (typically 200), medium input resistance and a high output resistance. 6. How does transistor work as amplifier?A transistor acts as an amplifier by raising the strength of a weak signal. The DC bias voltage applied to the emitter base junction, makes it remain in forward biased condition. ... Thus a small input voltage results in a large output voltage, which shows that the transistor works as an amplifier. 7. What is common emitter amplifier circuit?The Common Emitter Amplifier circuit has a resistor in its Collector circuit. The current flowing through this resistor produces the voltage output of the amplifier. ... The Base of the transistor used in a common emitter amplifier is biased using two resistors as a potential divider network. 8. What are the main parts of a transistor amplifier circuit?A Single stage transistor amplifier has one transistor, bias circuit and other auxiliary components. The following circuit diagram shows how a single stage transistor amplifier looks like. When a weak input signal is given to the base of the transistor as shown in the figure, a small amount of base current flows. 9. What is the phase difference in common emitter amplifier?The phase difference between the input and output voltage of CE amplifier circuit is. The phase difference of 1800 between the signal voltage and output voltage in a common emitter amplifier is known as phase reversal. 10. When an NPN transistor is used as an amplifier?For a npn transistor to be used as an amplifier, forward bias has to be applied on the transistor. Thus, when an npn transistor is used as an amplifier, holes move from base to emitter. So, the correct answer is option D i.e. holes move from base to emitter. 11. When an NPN junction transistor is used as an amplifier in CE mode?A transistor is used in the common emitter mode as an amplifier then: (A) the base emitter junction is forward baised. (B) the base emitter junction is reverse baised. (C) the input signal is connected in series with the voltage applied to bias the base emitter junction. 12. How is an NPN transistor used as an amplifier show with its circuit diagram?The circuit of a common-emitter amplifier using an n-p-n transistor is shown below : In a common emitter amplifier circuit, the input signal voltage and output collector voltage are in opposite phase. i.e 180° out of phase. Thus the phase difference between the input signal and output voltage is 180°. 13. How does a common emitter amplifier work?Operation of Common Emitter AmplifierWhen a signal is applied across the emitter-base junction, the forward bias across this junction increases during the upper half cycle. This leads to an increase in the flow of electrons from the emitter to a collector through the base, hence increases the collector current. 14. What is β for a CE configuration?Base Current Amplification Factor (β)The base current amplification factor is defined as the ratio of the output and input current in a common emitter configuration. In common emitter amplification, the output current is the collector current IC, and the input current is the base current IB. 15. What is current gain CE configuration?The current gain of a transistor in CE configuration is defined as the ratio of output current or collector current (IC) to the input current or base current (IB). The current gain of a transistor in CE configuration is high. Therefore, the transistor in CE configuration is used for amplifying the current.
kynix On 2021-11-30
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